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12n^2-108=0
a = 12; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·12·(-108)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*12}=\frac{-72}{24} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*12}=\frac{72}{24} =3 $
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